Question

If the stopping potential of a metal when illuminated with a radiation of wavelength 480 nm is 1.2 V. Find
a) the work function of the metal
b) the cutoff wavelength of the metal
c) the maximum energy of the ejected electrons.​

Answer 1

Answer:

Work-function =0.6 eV

and E=2 eV

Hence; Using Photoelectric effect :

E=work−function+(K.E)

max

=ϕ+(K.E.)

max

Hence, (K.E.)

max

=E−ϕ

⇒eV

0

=(2−0.6) eV

⇒

V

0

=1.4 volts