If the straight line, 2x – 3y + 17 = 0 is perpendicular to the line passing through the points (7, 17) and (15, β), then β equals:
(A) 35/3
(B) –5
(C) –35/3
(D) 5
Answers
Answer:
d) 5
Step-by-step explanation:
step 1 rearrange the eq y=mx+c where m is slope of given line.
step 2 slope of perpendicular line m' = -1/m
step 3 equate m'= y2-y1/x2-x1 where any of y is beta
Answer:
11th
Maths
Straight Lines
Distance of a Point from a Line
If the straight line, 2x - ...
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Asked on December 27, 2019 by
Malavika Sankaran
If the straight line, 2x−3y+17=0 is perpendicular to the line passing through the points (7, 17) and (15,β) then equals :
MEDIUM
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ANSWER
Given 2x−3y+17=0 ……………. (1)
is a line perpendicular to line passing through point P(7,17) & Q(15,β) then
equation of line passing throught P & Q is
y−17=(
15−7
β−17
)(x−7)
8y−136=βx−7β−17x+119
(7−β)x+8y−255=0 ………... (2)
Line (1) & (2) are perpendicular to each other then
m
1
m
2
=1
Product of slopes of line (1) & (2) is −1
Now,
m
1
=
3
2
and m
2
=
8
β−7
m
1
m
2
=−1⇒
3
2
(
48
β−7
)=−1
β−7=−12
β=−12+7=−5
Hence [β=−5].