If the straight line (3x+4y+5)+k(x+2y-3)=0 is parallel to x axis then value of k is ?
Answers
Answered by
58
Regroup the equation:
(3x + 4y + 5) + k(x + 2y - 3) = 0
3x + 4y + 5 + kx + 2ky - 3k = 0
(3 + k)x + (4 + 2k)y + (5 -3k) = 0
If the equation is parallel to the x-axis:
the coefficient of x must be equal to 0
3 + k = 0
k = -3
Answer: k = -3
Answered by
24
Answer:
k = - 3
Step-by-step explanation:
Given If the straight line (3x+4y+5)+k(x+2y-3)=0 is parallel to x axis then value of k is
Multiplying the above equation we have
3x + 4y + 5 + kx + 2ky - 3k = 0 Grouping the given terms we have
(3 + k)x + (4 + 2y)k + 5 - 3k = 0
Since the two lines are parallel, the slope of the given line is equal to the slope of x- axis. So coefficient of x is zero. The coefficient of x is (3 + k).
3 + k = 0
k = - 3
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