Question

If the straight line px - y =0 is out
side the circle x^2+ y^2 - 20y +90 =0
then?​

Answer 1

Answer:

The intersection of line and circle is

x

2

+x

2

m

2

−20mx+90=0

⇒x

2

(1+m

2

)−20mx+90=0

Since, the line lies outside the circle.

∴ D<0

⇒400m

2

−4×90(1+m

2

)<0

⇒40m

2

<360⇒m

2

<9

⇒∣m∣<3