if the string of a conical pendulum makes an angle theta with the horizontal then the square of its time period is proportional to? 1) sin (theta) 2)cos (theta) 3) tan (theta) 4) cot (theta)
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time period for conical pendulum= T = 2λ√r/gtan0
T²= 4λ²r/ gtan0 α cot ∅
r= radius
g = acceleration due to gravity
HEnce the square of time period is directly proportional to cot∅
T²= 4λ²r/ gtan0 α cot ∅
r= radius
g = acceleration due to gravity
HEnce the square of time period is directly proportional to cot∅
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Answer:
answer is sin tetha
Explanation:
refer the attachment.
Attachments:
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