Question

if the sum and difference of zeeos of quadratic polynomial are -3 and -10 respectively then find the product of the other two zeros​

Answer 1

Step-by-step explanation:

α+β= -3

α-β= -10

sqaring on both sides of two

α^2+β^2+2αβ= -3

α^2+β^2-2αβ= -10

by subracting both

4αβ = 7

αβ=7/4

Answer 2

Sum of zeroes = α+β=-3 ..(1)

Difference of zeroes= α-β=-10 ..(2)

Adding equation (1) and (2), we get

2α=-13

α=-13/2

Substituting the value of α in equation (1)

-13/2 +β=-3

β=-3+13/2

β=7/2

Product of zeroes =αβ=(-13/2) ×7/2=-91/4