Question

If the sum and difference of zeroes of quadratic polynomial are -3 and -10 respectively. Then find the difference of the square of the zeroes.​

Answer 1

Step-by-step explanation:

Let zeroes of quadratic equation are a and b .

a+b= -3

a-b= -10

We have to find $a^{2}-b^{2}$

$a^{2}-b^{2}=(a-b)(a+b)\\a^{2}-b^{2} = (-10)(-3)\\a^{2}-b^{2}=30 Answer$