Question

If the sum and difference of zeroes of quadratic polynomial are -3 and -10 respectively. Then find the difference of the square of the zeroes.​

Answer 1

x

2

−2x−15=0

Step-by-step explanation:

sum of zeroes= 2

product of zoroes= -15

Now,

{x }^{2} - ( \alpha + \beta )x + \alpha \beta = 0x

2

−(α+β)x+αβ=0

{x}^{2} - (2)x + ( - 15) = 0x

2

−(2)x+(−15)=0

{x}^{2} - 2x - 15 = 0x

2

−2x−15=0