Math, asked by Samiksha3568, 10 months ago

If the sum and the product of the roots of the quadratic equation ax square - 5x + c = 0 are both equal to 10, find the values of a and b

Answers

Answered by GeniusYH
2

Answer:  

Step-by-step explanation:

 We know that


ax² - 5x + c = 0  

a = a,  b = -5, c = c

 Sum of the roots = α + β = (-b)/(a) = 10

=> 5/a = 10

Hence a = (1/2)

 Product of the roots = αβ = (c)/(a) = 10

=> (c)/(1/2) = 10

=> 2c = 10

Hence c = 5.

 Given b = -5

 Hope my answer helps you

 Harith

Answered by shadowsabers03
2

\bold{Answer:}

a = \bold{\frac{1}{2}} \\ \\ b = \bold{5}

\bold{Step}$-$\bold{by}$-$\bold{step\ explanation:}

p(x) = ax^2 - 5x + b = 0 \ \ \ [$Taking$\ c\ $as$\ b\ $for the question] \\ \\ Let the roots be \alpha\ $and \beta. \\ \\ \alpha + \beta = -\frac{-5}{a} = \frac{5}{a} = 10 \\ \\ a = \frac{5}{10} = \bold{\frac{1}{2}} \\ \\ \\ \alpha \beta = \frac{b}{a} = \frac{b}{\frac{1}{2}} = b \div \frac{1}{2} = b \times 2 = 2b = 10 \\ \\ b = 10 \div 2 = \bold{5}


\therefore\ $Values of$\ a\ $and$\ b\ $are$\ \bold{\frac{1}{2}}\ $and$\ \bold{5}\ $respectively. \\ \\ \therefore\ p(x) = \frac{1}{2}x^2 - 5x + 5 = 0 \\ \\ \therefore\ \alpha = 5 + \sqrt{15} \ \ \ ; \ \ \ \beta = 5 - \sqrt{15}


$$Thank you. Have a nice day. :-)$ \\ \\ \\ \#adithyasajeevan

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