Question

if the sum and the.product of two numbers are 7 and 45/4 respectively, find the be sum of thier cubes​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

let x and y be the two numbers

x+y=7

xy=4

$\ {x}^{3 } + {y}^{3} = (x+ y) (x2 − xy + y 2 ).$

{x+y)^2=49={x}^{2} + {y}^{2} + 2xy

49={x}^{2} + {y}^{2} +8 since xy= 4

x^2+y^2=41

required x

${x}^{3} + {y}^{ 3} = (7)(41 - 4) = 7(37) = 259$