if the sum and the product of two numbers are 7 and 45/ 4 respectively, the sum of their cubes.
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Answer:
let the numbers be a and b
Step-by-step explanation:
A.T.Q , it is given that
a+b=7
a × b=45/4
from equation 1 we get
a=7-b
now put this value in equation number 2
(7 - b) b= 45/4
7b - b²= 45/4
y²- 7b + 45/4=0
4y²-28b+45=0
4b²-18b-10b+45=0
2b(2b-9) -5(2b-9) =0
(2b-9) (2b-5) =0
b=9/2, b=5/2
put y=9/2 in any equation we get
a=5/2
sum of cubes=(5/2) ³+(9/2) ³
=125/8+729/8
=854/8
=427/4
hence the value of their cube is 427/4
thank you
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