if the sum and the products of the roots of the equation kx^2+6x+4k=0 are equal then k=? its urgent
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Answered by
89
kx^2+6x+4k=0
here,a=k
b=6
c=4k
we know.sum of roots= -b/a
so, here sum of the roots= -6/k
& product of roots=c/a
here, product of roots=4k/k=4
A.C.Q, -6/K=4
4k=-6
k= -3/2
Answered by
41
SOLUTION :
Option (a) is correct : - 3/2
Given : kx² + 6x + 4k = 0 and sum and product of roots are equal.
On comparing the given equation with ax² + bx + c = 0
Here, a = k , b = 6 , c = 4k
Sum of roots = - b/a
Sum of roots = - 6/k
Product of roots = c/a
Product of roots = 4k/k
Product of roots = 4
Given : sum of roots = Product of roots
-6/k = 4
4k = - 6
k = -6/4
k = - 3/2
Hence, the value of k is - 3/2.
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