If the sum is three time the initial in three years compounded anually
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![= > s = p(1 + \frac{r}{100} ) ^{t} \\ \\ = > 3p = p {(1 + \frac{r}{100}) }^{3} \\ \\ = > 3 = {(1 + \frac{r}{100} )}^{3} \\ \\ or. \: \: \sqrt[3]{3} = 1 + \frac{r}{100} \\ \\ = > r = 100( \sqrt[3]{3} - 1) = 100(1.44 - 1) \\ \\ = > \bf \: r = 100 \times 0.4422 = 44.22\%](https://tex.z-dn.net/?f=+%3D++%26gt%3B+s+%3D+p%281+%2B++%5Cfrac%7Br%7D%7B100%7D+%29+%5E%7Bt%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+3p+%3D+p+%7B%281+%2B++%5Cfrac%7Br%7D%7B100%7D%29+%7D%5E%7B3%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+3+%3D++%7B%281+%2B++%5Cfrac%7Br%7D%7B100%7D+%29%7D%5E%7B3%7D++%5C%5C++%5C%5C+or.+%5C%3A++%5C%3A++%5Csqrt%5B3%5D%7B3%7D++%3D+1+%2B++%5Cfrac%7Br%7D%7B100%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+r+%3D+100%28+%5Csqrt%5B3%5D%7B3%7D++-+1%29+%3D+100%281.44+-+1%29+%5C%5C++%5C%5C++%3D++%26gt%3B++%5Cbf+%5C%3A+r+%3D+100+%5Ctimes+0.4422+%3D+44.22%5C%25 "= > s = p(1 + \frac{r}{100} ) ^{t} \\ \\ = > 3p = p {(1 + \frac{r}{100}) }^{3} \\ \\ = > 3 = {(1 + \frac{r}{100} )}^{3} \\ \\ or. \: \: \sqrt[3]{3} = 1 + \frac{r}{100} \\ \\ = > r = 100( \sqrt[3]{3} - 1) = 100(1.44 - 1) \\ \\ = > \bf \: r = 100 \times 0.4422 = 44.22\%")
So the required rate of interest = 44.22%
Hope this is ur required answer
Proud to help you
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So the required rate of interest = 44.22%
Hope this is ur required answer
Proud to help you
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