If the sum of 1st 11 terms of an a.P is equal to sum of 1st 19 terms of that a.P then, find the sum of 1st 30 terms
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Step-by-step explanation:
sum of 11 terms = (11/2)(a + a+10d)
= 11a + 55d
sum of 19terms = (19/2)*(a+a+18d)
=19a + 171d
11a + 55d = 19a + 171d
-8a = 116d
2a +29d = 0
som of 30 terms = (30/2)(a + a +29d)
= 15* (2a + 29d)
= 15 * 0
= 0
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