If the sum of 1st 9 terms of an AP is
equal to the sum of 1st 13 terms, the
sum of 1st 22 terms will be
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Answer:
s=s`
9/2(2a+8d) =13/2(2a+12d)
18a+72d=26a+156d
0=8a+84d
-8a=84d
a=-21/2d
S°=11(-21d+21d)
S°=0
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