if the sum of 2 consecutive
multiples of 7 are 693 Find the
nos
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38
Given:
Sum of 2 consecutive multiples of 7 is 693
To Find:
Numbers following above condition
Solution:
Let the two numbers be 7n and and 7(n+1) where n is a natural number.
Now, according to question
⇒ 7n+7(n+1)= 693
⇒ 7n+7n+7= 693
⇒ 14n+7= 693
⇒ 14n= 693-7
⇒ 14n= 686
So, the required numbers are
⟼ 7n= 7(49)= 343
⟼ 7(n+1)= 7(49+1)= 7(50)= 350
Hence, the required numbers are 343 and 350.
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