Question

If the sum of 2 distinct natural numbers is 126 and their HCF is 9, then how many pairs of such numbers are possible?​

Answer 1

Step-by-step explanation:

First of all we will divide 126 by 9, we will get 14 as a result…

Now for sum as 14, pairs are (1,13)(2,12)(3,11)(4,10),(5,9)(6,8)(7,7)

Now multiply these pair by 9,we will get (9,117)(18,108)(27,99)(36,90)(45,81)(54,72)(63,63)

Required number of pairs are 7 whose sum is 126 and hcf is 9