If the sum of 2 numbers is 9 and the sum of their reciprocals is 1/2.Find the numbers
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let the numbers be x and y
x+y=9 therefore x=9-y
and
1/x+1/y=1/2; 1/(9-x)+1/x=1/2; x^2-9x+18=0; x=6 therefore y=3
x+y=9 therefore x=9-y
and
1/x+1/y=1/2; 1/(9-x)+1/x=1/2; x^2-9x+18=0; x=6 therefore y=3
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