Question

if the sum of 3 consecutive integers is 540. then integers are​

Answer 1

Given,

The sum of $3$ consecutive integers is $540$

We have to find the three integers

Let, first integer be $x$

Second integer be $x+1$

Third integer be $x+2$

According to the question,

$x+x+1+x+2=540$

$3x+3=540$

$3x=540-3$

$3x=537$

$x= \frac{537}{3}$

$x=179$

Now substitute $x=179$ in integers

First integer $x=179$

Second integer $x+1=179+1=180$

Third number $x+2=179+2=181$

$179+180+181=540$

Therefore, the three integers are $179,180$ and $181$.

Answer 2

Given,

The sum of  consecutive integers is $540$

We have to find the three integers

Let, first integer be $z$

The Second integer will be $z+1$

The third integer be $z+2$

As per the  given  condition ,

$z+z+1+z+2=540$

$3z+3=540\\3z=540-3\\3z=537\\z= 179$

After putting the value

$z = 179$ in integer

Second integer

               $z+1 = 179+1\\= 180$

Third integer $z+2$

                 =  179+2

                  =  181

 Adding Above the three

we get ,

= 179+180+181

= 540

Hence ,

The three consrcutive integers of 540 is 179,180,and 181