Question

if the sum of 3 no's. in ap is 24 and their products is 440, find the no's.​

Answer 1

Step-by-step explanation:

If the sum of three numbers in A.P., is 24 and their product is 440, find the numbers. Let the three numbers in A.P. be a – d, a, and a + d. Therefore, when d = 3, the numbers are 5, 8, and 11 and when d = –3, the numbers are 11, 8, and 5. Thus, the three numbers are 5, 8, and 11.

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Answer 2

Answer:

Step-by-step explanation:

Let the three numbers be a-d, a, a+d.

Given,

Sum of three numbers = 24

=> a - d + a + a + d = 24

=> 3a = 24

=> a = 8

Product of three numbers = 440

=> (a - d )(a)(a + d) = 440

=> (a - d)(a + d) = 440/a

=> (a - d) (a + d) = 440/8 = 55   ( ∵ a = 8)

=> a² - d² = 55

=> 8² - d² = 55

=> d² = 64 - 55 = 9

=> d = ±3

When d = +3,

The number series is:  8 - 3, 8, 8 +3 = 5, 8 , 11

When d = -3,

The number series is : 8 - (-3), 8, 8 + (- 3) = 11, 8, 5