If the sum of 3 number in
a.P is 45 and product is 3135 .Find common different
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Here is your answer buddy,
Let the numbers be a−d, a and a+d, clearly d is the common difference.
Now,
The 3 numbers are in AP.
Therefore,
By adding up three numbers we get,
a-d+a+a+d = 45
=> 3a = 45 ( d and d get cancelled)
=> a = 15 ---------(1)
Again,
By multiplying the three numbers we get,
(a-d)×a×(a+d) = 31315
=> {}×(a+d) =3135
=> =3135
=> =3135
(from 1)
=> 3375 - 225d + 225d - 15d = 3135
=> 3375 - 15d = 3135
(225d and 225 d get cancelled)
=> - 15d = 3135 - 3375
=> - 15d = - 240
=> d = 16 (minus got cancelled)
So the common difference is 16.
Hope this helps you.
Be Brainly.
Let the numbers be a−d, a and a+d, clearly d is the common difference.
Now,
The 3 numbers are in AP.
Therefore,
By adding up three numbers we get,
a-d+a+a+d = 45
=> 3a = 45 ( d and d get cancelled)
=> a = 15 ---------(1)
Again,
By multiplying the three numbers we get,
(a-d)×a×(a+d) = 31315
=> {}×(a+d) =3135
=> =3135
=> =3135
(from 1)
=> 3375 - 225d + 225d - 15d = 3135
=> 3375 - 15d = 3135
(225d and 225 d get cancelled)
=> - 15d = 3135 - 3375
=> - 15d = - 240
=> d = 16 (minus got cancelled)
So the common difference is 16.
Hope this helps you.
Be Brainly.
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