Question

if the sum of 3 rd and 8th term of an a.p. is 7 and sum of 7th and 14 th terms id -3 then find the 10 th term

Answer 1

Hey friend,

Here is your answer,
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Let first term be a , common difference be d & number of term be n.


T₃ + T₈ = [a+(3-1)d] + [a+(8-1)d]

     7      = a + 2d + a + 7d

     7      =  2a + 9d              ----------------------(i)


T₇ + T₁₄ = [a+(7-1)d] + [a+(14-1)d]

    - 3     =  a + 6d + a + 13d

   - 3      =  2a + 19d            ----------------------(ii)


(ii) - (i) 

=> - 3 - 7  =  10d

=>   - 10   =  10d

=>    - 1    =   d


Put d = -1 in (i)

   7   =  2a + 9*(-1)

  7    =  2a - 9

  2a  =   16

    a = 8


T₁₀ = a + (10-1)*(-1)
      => 8 + 9(-1)
      => 8 - 9
      => -1
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Hope this helped you !!
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Answer 2

Answer:

I hope it is helpful to you