if the sum of 3 term of ap is 27 .than find the first terms
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Step-by-step explanation:
sum of n terms of an ap is (n/2)(2a+(n-1)d)
given the sum of 3 terms of ap is 27
then 27=(3/2)(2a+(3-1)d)
27= (3/2)(2a+2d)
27=(3/2)(2(a+d))
27=3(a+d)
(27/3)=a+d
a+d= 9
if you give total question I can solve totally
you given only half question so l solved only half question
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