if the sum of 3rd and 10th term of an increasing ap is 39 while the difference between the 7th and 11th terms 12 find the 2nd term
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Step-by-step explanation:
a+2d+a+9d=39
2a+11d=39
a+6d-a-10d=12
d=-3
Substituting d value in the following,
2a+11x-3=39
2a-33=39
2a =39+33=72
a=36
a2=36+(-3)=33
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