If the sum of 3rd and 4th term is 19 and sum of 5th and 7th term is 34 then write AP
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Answer: The series is 2,5,8
Step-by-step explanation:
If the sum of 3rd and 4th term is 19 and sum of 5th and 7th term is 34 then write AP
an=a+(n-1)d
Here,a3=a+(3-1)d
=a+2d
a4=a+(4-1)d
=a+3d
Therefore,
=a+2d+a+3d=19
=2a+5d=19 equation1
Here,a5=a+(5-1)d
=a+4d
a7=a+(7-1)d
=a+6d
Therefore,
=a+4d+a+6d=34
=2a+10d=34 equation2
Subtract equation1 from equation1
2a+10d=34
-2a+5d=19
5d=15
d=3
Hence, we get the common difference is 3
Now we have to find the first term by substitutind common difference in equation 1 or 2
2a+10d=34
2a+10x3=34
2a+30=34
2a=34-30
2a=4
a=2
Therefore,
a1=a=2
a2=a+d=2+3=5
a3=a+2d=2+(2x3)=8
Hence, we get the series 2,5,8
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