if the sum of 3rd and 4th term is 7 and the sum of 7th and 14th sum is -3 then find 10th term
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Answer:
a3=a+2d, a4=a+3d.
a7=a+6d, a14=a+13d.
Given that
a3+a4=7. a7+a14=-3.
a+2d+a+3d=7. a+6d+a+13d=-3.
2a+5d=7. 2a+19d=-3.
a+5d=7/2......(1). a+19d=-3/2......(2).
On substracting (1) from (2).
a+5d=7/2.
a+19d=-3/2.
(-) (-) (+)
-14d=10/2.
-14d=5.
d=5/-14.
d=-5/14.
From Eqn. (1).
a+5d=7/2.
a+5(-5/14)=7/2.
a-25/14)=7/2.
a=7/2+25/14.
a=98+50/28.
a=148/28.
a=74/14.
a=37/7.
an=a+(n-1)d.
a10=37/7+(10-1)(-5/14).
=37/7+(9)(-5/7).
=37/7-45/7.
=-8.
I think this is your answer.
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