if the sum of 3rd and 5th term of an ap is 8 and the sum of the 7th and 13 term is minus 2 then find the 10th term.
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Answer:
-1
Step-by-step explanation:
Sum of 3rd and 5th term = 8
a+2d + a+4d = 8
2a+6d=8
a+3d=4
Sum of 7th and 13 th term= -2
a+6d + a+12d = -2
2a+18d= -2
a+9d = -1
From both eqn= we get .
a+9d= -1
a+3d= 4
________
6d= -5
d= -5/6
a+3d=4
a= 4- 3d= 4- (3*-5/6)
= 13/2
so a=13/2 and d= -5/6
10 th term= a+9d= 13/2 + (9*-5/6)
= 13/2 - 15/2
= -1
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