If the sum of 3rd and 8th term of an arithmetic progression is 7and the sum of 7th and 14th term is -3. Find the 10th term?
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answer -1
pls refer my attachment:
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Step-by-step explanation:
a3+a8=7
a+2d+a+7d=7
2a+9d=7............1
a7+a14=-3
a+6d+a+13d=-3
2a+19d=-3...........2
from 1 and 2
2a+9d=7
2a+19d=-3
-10d=-10
d=1
put d value in equation1
2a+9×1=7
2a=7-9
2a=-2
a=-1
a10=a+9d
a10=8
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