Question

If the sum of 60%of a fractionl nbr and the nbr square root is 5 greater than one fifth of the nubr the nbr is

Answer 1

i don't know



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Answer 2

Let n = the fractional number
.6n +  = n + 5
We can write 1/5 as .2
.6n +  =.2n + 5
subtract .6n from both sides
 = .2n - .6n + 5= -.4n + 5
square both sides
n = (-.4n+5)^2
n = .16n^2 - 2n - 2n + 25
n = .16n^2 - 4n + 25
0 = .16n^2 - 4n - n + 25
A quadratic equation
.16n^2 - 5n + 25 = 0
using the quadratic formula; a=.16; b=-5; c=25
I got two solution, but only one was fractional
n = 6.25 or 6 is the number
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you can confirm this for yourself, replace n with 6.25 in the original equation
.6(6.25) +  = (6.25) + 5