Question

If the sum of a boy's age and his father's age is 24 years and the fourth part of the product of their age exceeds the boys age by 9 years . Find the present age

Answer 1

suppose boy age be X years.
then father age will be = ( x- 24) years
A.T.Q
1/4(X)(24 -4) = X + 9
X(24 - 4) = 4(X + 9)
X2 - 20X + 36 =0
X2 - 2X -18X + 36= 0
X(X - 2) - 18(X -2) =0
X = 2 ,18
IF BOY AGE BE 2 YEARS ,THEN FATHER AGE BE 24 - 2= 22 YEARS
FATHER AGE MUST BE GREATER THAN SON.