if the sum of a certain number of terms of the A.P.25,22,19,......is 116,find the last term
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a=25
d=-3
an=116
an=a+(n-1)*d
-116=25+(n-1)*-3
-116-25=(n-1)*-3
-141/-3=n-1
47=n-1
n=47+1
n=48
d=-3
an=116
an=a+(n-1)*d
-116=25+(n-1)*-3
-116-25=(n-1)*-3
-141/-3=n-1
47=n-1
n=47+1
n=48
Ni77:
Are you sure,its the sum of certain number of terms of the AP
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