Question

If the sum.Of a number and its square is 380,what is the number

Answer 1

let the no be x
ATQ
${x}^{2} + x = 380 \\ {x}^{2} + x - 380 = 0 \\ {x}^{2} + 20x - 19x - 380 = 0 \\ x(x + 20) - 19(x + 20) = 0 \\ (x + 20)(x - 19) = 0 \\ x + 20 = 0 \: \: or \: \: x - 19 = 0 \\ x = - 20 \: \: or \: \: x = 19$
Required no -20 or 19

Answer 2

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