Question

if the sum of a quadratic polynomial of 3 x square minus kx + 6 equal to 3 then find the value of k​

Answer 1

Answer:

k = 9

Step-by-step explanation:

Sum of zeroes = 3

3x^2-kx+6

a = 3

b = -k

c = 6

sum of zeroes = -b/a

α + β = -b/a

3 = -(-k)/3

3 x 3 = k

k = 9

Answer 2

Step-by-step explanation:

Given,

3x^2-kx+6=3

Let,

3x^2-kx =3-6

3x^2-kx =-3

-kx =-3-3x^2

-1×kx =-3(1+x^2)

kx = -3(1+x^2)÷-1

kx = 3(1+×^2)

k =3(1+x^2)÷x

let,

k=3(1+x^2)÷x