Question

If the sum of acute angles tan inverse of 'x and tan inverse of1/2
is 45°, then the value of x is equal to
​

Answer 1

Answer:

${ \tan }^{ - 1} x + { \tan }^{ - 1} \frac{1}{2} = 45 \\ { \tan}^{ - 1} ( \frac{x + \frac{1}{2} }{1 - \frac{x}{2} } )= 45 \\ \tan(45) = \frac{ \frac{2x + 1}{2} }{ \frac{2 - x}{2} } \\ \frac{2x + 1}{2} = \frac{2 - x}{2} \\ 2x + 1 = 2 - x \\ x = \frac{1}{3}$

Hope its help uh❤