Question

If the sum of ages of father and his son in years is 45 and thrice the difference of their ages in years is same as sum of ages.find the age of father

Answer 1

solutions :-
Let father's age be x

son age be y

A/q

x+y=45..................(1)

3(x-y)=45
3x-3y=45................ (2)

multiply 3 in equation (1)

3x+3y=135
3x-3y=45
=6x=180
x=180/6
x=30

Father's age is 30 years

Answer 2

"The age of father is 30.

Given:

The father's age is considered as x

The son's age is considered as y

To find:

The age of Father = ?

Solution:

$x+y=45\quad \quad \quad \rightarrow (1)$

3(x-y)=45

Father age +son age=45

$x+y=45\quad \quad \quad \rightarrow(1)$

3(Father age + son age)=45

3(x-y)=45

$3x-3y=45\quad \quad \quad \rightarrow(2)$

Equation (1) multiplied my 3

3(x+y=45)

$3x+3y=135\quad \quad \quad \rightarrow(3)$

$3x-3y=45\quad \quad \quad \rightarrow(4)$

By simplifying the equation (3) and (4)

6x=180

6 goes to right hand side as dividend

$x=\frac{180}{6}$

x=30"