If the sum of ages of Father and his son in years is 64 and twice I he difference of their ages in years is same as sum of ages then find the age of Father.
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let fathers age be x and sons age y
then x+y=64_(1)
given 2(x-y)=64
=2x-2y=64.....(2)
x + y =64.....(1)
=(1)×2= 2x+2y=128...(3)
2x- 2y =64....(2)
(3)+(2)= 4x= 192
x=192/4
x=48
substitute x in (1)
48+y=64
y=64-48
y=16
ie. father is 42 and son is 16 years old.
hope this helps you mate.
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