if the sum of all interior angles of a polxgon is 2340 find the number of sides in the polygon
Answers
Answered by
5
Sum of all interior angles =2n - 4 right angle
2340 =2n - 4×90
2340 /90 =2n - 4
26 +4 = 2n
30 = 2n
30 / 2 = n
15 = n
Number of side = 10 sides
2340 =2n - 4×90
2340 /90 =2n - 4
26 +4 = 2n
30 = 2n
30 / 2 = n
15 = n
Number of side = 10 sides
Similar questions
Science,
8 months ago
Social Sciences,
8 months ago
Science,
8 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Hindi,
1 year ago
Hindi,
1 year ago
Hindi,
1 year ago