Question

If the sum of any two integers is 3 and the difference of the squares is 1 then the difference of them is

Answer 1

Answer:

1/3

Step-by-step explanation:

Let the two integers be 'a' and 'b'

a+b=3

a²-b²=1

(a+b)(a-b) = 1

   3(a-b) = 1

a-b = 1/3

∴ The difference of the numbers is 1/3

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Answer 2

Answer:

x+y=3

$x^{2} -y^{2}$=1

x^2-y^2=(x+y)(x-y)

3(x-y)=1

x-y=1/3