if the sum of area of two circle with radi R¹ and R² is equalbto the area of a circle of radius R , then
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ar.circle with radius R1 =π R1^2 and ar.circle with radius R2 =πR2^2.
∴sum of the areas =π(R1^2+R2^2).
Again ar.circle with radius R=πR^2.
∴By the given condition π(R1^2+R2^2)=πR^2
⟹(R1^2+R2^2)=R^2.
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