If the sum of digits of
a two-digit number is
greater than 9, then
the product of the
digits of the number
will always be
greater than:
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Let the unit digit be y and tens digit be x
Number formed = 10x + y
Reverse number = 10y + x
x + y = 9 (Given)…………………………eq1
10y + x = 10x + y + 27…………………….eq2
9y - 9x = 27
y - x = 3……………………………………..eq3
Solving eq1 and eq3 ,we get
x = 3 and y = 6
Original Number = 36 Reversed Number = 63
You can crosscheck the answer by putting up the values obtained either in eq1 or eq2 or eq 3
Thank You !
Answered by
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Answer:
hinmo 8ucboiv 9b in in NJ Bibi e. I
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