Question

if the sum of first 14 term is 1050 and the first term is 10 find the 20 term​

Answer 1

Step-by-step explanation:

sum of nth term = n/2[2a+(n-1)d]

sum of 14th term = 14/2[2*10+(14-1)d]

1050 = 7[20+13d]

1050 = 140+ 91d

1050 - 140 = 91d

910 = 91d

d = 910/91

d = 10

now 20th term

Tn = a+(n-1)d

T20 = 10+(20-1)10

T20 = 10+190

T20 = 200

Answer 2

Answer:

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