if the sum of first 14 term of and AP is 1050 and firt term is 10 find the 20th term
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a=10
S 14=1050
=14/2[20+13 d]=1050
=7[20+13 d]=1050
=20+13 d=150
d=10
20th term=a+19 d
=10+19×10
=10+190
=200
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The answer is a20 = -380
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