Question

if the sum of first 14 terms of an ap is 1050 and its first term is 10 find the 20th term​

Answer 1

Answer:

Sn = n/2 (2a + (n-1)d)

S14 = 14/2 (2×10 + 13d)

1050 = 7 (20 + 13d)

1050/7 = 20 + 13d

150 - 20 = 13d

130 = 13d

d = 130/13

d = 10

A20 = a + 19d = 10 + 19×10 = 10 + 190 = 200

20th term is 200

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Answer 2

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SOLUTION

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HERE ,

Sn=1050; n=14,a=10

Sn= n/2 【2a+13】 = 140+91d

910 = 91d

.

. . d = 10

.

. . a20=10+ 【2a-1】10

| a20 = 200

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