If the Sum of first 4terms of an AP is 40 then find first term
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Given :
Sum of first 4 terms of an AP = 40
Solution :
Let the first 4 terms be ;
a - 3d , a - d , a + d , a + 3d
According to the question ,,,
a - 3d + a - d + a + d + a + 3d = 40
Common difference d gets cancelled and we get ,,,
4a = 40
a = 10
Therefore ,,,, the first term ( a ) is 10
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