if the sum of first 7 terms of an A.P is 49 and that of 17 term is 289 find the sum of first n terms
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Answer:
n^2
Step-by-step explanation:
49=7/2[2a+(6)d]
7=a+3d------1
289=17/2[2a+16d]
17=a+8d-----2
Solving 1 and 2
a+3d=7
a+8d=17
==== - 5d=-10
d=2
Sub in 1 or 2 to get the value of a which is 1
Now
Sn=n/2[2(1)+(n-1)2]
=n^2
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Hope it helps
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