If the sum of first 9 terms of an ap is 81 and that of first 17 terms is 289 find the sum of first n term
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81 = 9/2 (2a+8d)
400 = 20/2 (2a +19d)
a, 40 = 2a +19d
162 = 18a + 72d
2a + 19d = 40
18a + 72d = 162
18a + 171d = 360
18a + 72d = 162
99d = 198
d = 198/99 = 2 (answer)
81 = 9/2 (29 + 8x2)
162 = 18a + 144
a, 162 - 144/18 = a; a = 18/18
a, a = 1 (answer)
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