Question

If the sum of first 99 terms of an AP is 99 what will be its 50th terms​

Answer 1

Answer:

$T_{50}=1$

Step-by-step explanation:

$S_{99}=99/2(2a+98d)\\99=99/2(2a+98d)\\2=2(a+49d)\\a+49d=1$

For 50th Term n=50 Therefore,

$T_{50}=a+(n-1)d\\=a+(50-1)d\\=a+49d\\=1$