If the sum of first k term of an
a.P is 3k square - k and its common difference is 6 then what is its first term
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Answer:
2-3k
Step-by-step explanation:
S=k/2 (2a+(k-1)d)
3k²-k=k/2 (2a+(k-1)6)
6k²-2k=2ak+6k²-6k
4k-6k²=2ak
a=2 - 3k
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