if the sum of first m tearms of an A.P. be n and the sum of first n tearm of the same A.P. be m , determine the sum of its (m+n) terms is
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Step-by-step explanation:
I don't know.
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Step-by-step explanation:
sum of 1st m terms = n
n = m[a+(m-1)d]/2
n = (ma + m²d - md)/2
sum of 1st n terms = m
m = n[a+(n-1)d]/2
m = (na + n²d - nd)/2
so, (m+n) = [(ma + m²d - md)+(na + n²d - nd)] / 2
(m+n) = (ma+na+m²d+n²d-md-nd) / 2
(m+n) = [a(m+n) +d(m²+n²) -d(m+n)]/2
(m+n) = [a(m+n) +d(m²-m+n²-n)] / 2
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