Question

If the sum of first n even natural numbers is equal to K times the sum of first n odd natural numbers, then K is equal to​

Answer 1

Step-by-step explanation:

sum of first n even numbers = n(n+1)

sum of first n odd numbers = n²

So,

n(n+1) = Kn²

n+1 = Kn

K = n+1 /n

Answer 2

Answer:

k=6/5

Step-by-step explanation:

let n=5

(2+4+6+8+10) = (1+3+5+7+9)

30=25k

k=30/25

k=6/5